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Using the truth table method, determine whether these formulas are:
(1) tautologous, contingent, or contradictory, (2) logically true or not, (3) satisfiable or not:

1. [Exercise 1] p ∧ q → p
p q p∧q p ∧ q → p
1 1 1 1
1 0 0 1
0 1 0 1
0 0 0 1

TAUTOLOGY, SATISFIABLE, LOGICAL TRUTH

2. [Exercise 2] p ∨ p → r
p r p ∨ p p ∨ p → r
1 1 1 1
1 0 1 0
0 1 0 1
0 0 0 1

CONTINGENT, SATISFIABLE, NOT A LOGICAL TRUTH

3. [Exercise 3] p ∨ (q → r)
p q r q → r p ∨ (q → r)
1 1 1 1 1
1 1 0 0 1
1 0 1 1 1
1 0 0 1 1
0 1 1 1 1
0 1 0 0 0
0 0 1 1 1
0 0 0 1 1

CONTINGENT, SATISFIABLE, NOT A LOGICAL TRUTH

4. [Exercise 4] (p → q) ∧ (q → r) → (p → r)
p q r p → q q → r (p → q) ∧ (q → r) p → r (p → q) ∧ (q → r) → (p → r)
1 1 1 1 1 1 1 1
1 1 0 1 0 0 0 1
1 0 1 0 1 0 1 1
1 0 0 0 1 0 0 1
0 1 1 1 1 1 1 1
0 1 0 1 0 0 1 1
0 0 1 1 1 1 1 1
0 0 0 1 1 1 1 1

TAUTOLOGY, SATISFIABLE, LOGICAL TRUTH

5. [Exercise 5] p → (q → r)
p q r q → r p → (q → r)
1 1 1 1 1
1 1 0 0 0
1 0 1 1 1
1 0 0 1 1
0 1 1 1 1
0 1 0 0 1
0 0 1 1 1
0 0 0 1 1

CONTINGENT, SATISFIABLE, NOT A LOGICAL TRUTH

6. [Exercise 6] p ∨ q → (r ∨ s → p)
p q r s p ∨ q r ∨ s r ∨ s → p p ∨ q → (r ∨ s → p)
1 1 1 1 1 1 1 1
1 1 1 0 1 1 1 1
1 1 0 1 1 1 1 1
1 1 0 0 1 0 1 1
1 0 1 1 1 1 1 1
1 0 1 0 1 1 1 1
1 0 0 1 1 1 1 1
1 0 0 0 1 0 1 1
0 1 1 1 1 1 0 0
0 1 1 0 1 1 0 0
0 1 0 1 1 1 0 0
0 1 0 0 1 0 1 1
0 0 1 1 0 1 0 1
0 0 1 0 0 1 0 1
0 0 0 1 0 1 0 1
0 0 0 0 0 0 1 1

CONTINGENT, SATISFIABLE, NOT A LOGICAL TRUTH

7. [Exercise 7] p ∧ q → q ∧ p
p q p ∧ q q ∧ p p ∧ q → q ∧ p
1 1 1 1 1
1 0 0 0 1
0 1 0 0 1
0 0 0 0 1

TAUTOLOGY, SATISFIABLE, LOGICAL TRUTH

8. [Exercise 8] (p → q) ∧ p → q
p q p → q (p → q) ∧ p (p → q) ∧ p → q
1 1 1 1 1
1 0 0 0 1
0 1 1 0 1
0 0 1 0 1

TAUTOLOGY, SATISFIABLE, LOGICAL TRUTH

9. [Exercise 9] (p → q) ∧ p ∧ ¬q
p q ¬q p → q (p → q) ∧ p (p → q) ∧ p ∧ ¬q
1 1 0 1 1 0
1 0 1 0 0 0
0 1 0 1 0 0
0 0 1 1 0 0

CONTRADICTION, UNSATISFIABLE, NOT A LOGICAL TRUTH

10. [Exercise 10] (p → q) ∧ (p → q)
p q p → q (p → q) ∧ (p → q)
1 1 1 1
1 0 0 0
0 1 1 1
0 0 1 1

CONTINGENT, SATISFIABLE, NOT A LOGICAL TRUTH

11. [Exercise 11] (p → q) ∧ q → p
p q p → q (p → q) ∧ q (p → q) ∧ q → p
1 1 1 1 1
1 0 0 0 1
0 1 1 1 0
0 0 1 0 1

CONTINGENT, SATISFIABLE, NOT A LOGICAL TRUTH

12. [Exercise 12] (p → q) ∧ ¬q → ¬p
p q ¬p ¬q p → q p → q ∧ ¬q (p → q) ∧ ¬q → ¬p
1 1 0 0 1 0 1
1 0 0 1 0 0 1
0 1 1 0 1 0 1
0 0 1 1 1 1 1

TAUTOLOGY, SATISFIABLE, LOGICAL TRUTH

13. [Exercise 13] (p → q) ∧ ¬p → ¬q
p q ¬p ¬q p → q (p → q) ∧ ¬p (p → q) ∧ ¬p → ¬q
1 1 0 0 1 0 1
1 0 0 1 0 0 1
0 1 1 0 1 1 0
0 0 1 1 1 1 1

CONTINGENT, SATISFIABLE, NOT A LOGICAL TRUTH

14. [Exercise 14] ¬(p ∧ q) ↔ ¬p ∧ ¬q
p q ¬p ¬q ¬p ∧ ¬q p ∧ q ¬(p ∧ q) ¬(p ∧ q) ↔ ¬p ∧ ¬q
1 1 0 0 0 1 0 1
1 0 0 1 0 0 1 0
0 1 1 0 0 0 1 0
0 0 1 1 1 0 1 1

CONTINGENT, SATISFIABLE, NOT A LOGICAL TRUTH

15. [Exercise 15] ¬(p ∧ q) ↔ ¬p ∨ ¬q
p q ¬p ¬q p ∧ q ¬(p ∧ q) ¬p ∨ ¬q ¬(p ∧ q) ↔ ¬p ∨ ¬q
1 1 0 0 1 0 0 1
1 0 0 1 0 1 1 1
0 1 1 0 0 1 1 1
0 0 1 1 0 1 1 1

TAUTOLOGY, SATISFIABLE, LOGICAL TRUTH (De Morgan's Law)

16. [Exercise 16] [(p → q) ∧ (q → r)] ∧ ¬(p → r)
p q r p → q q → r p → q ∧ q → r p → r ¬(p → r) (p → q) ∧ (q → r)] ∧ ¬(p → r)
1 1 1 1 1 1 1 0 0
1 1 0 1 0 0 0 1 0
1 0 1 0 1 0 1 0 0
1 0 0 0 1 0 0 1 0
0 1 1 1 1 1 1 0 0
0 1 0 1 0 0 1 0 0
0 0 1 1 1 1 1 0 0
0 0 0 1 1 1 1 0 0

CONTRADICTION, UNSATISFIABLE, NOT A LOGICAL TRUTH

17. [Exercise 17] p → (q ∧ ¬r → ¬q)
p q r ¬r ¬q q ∧ ¬r q ∧ ¬r → ¬q p → (q ∧ ¬r → ¬q)
1 1 1 0 0 0 1 1
1 1 0 1 0 1 0 0
1 0 1 0 1 0 1 1
1 0 0 1 1 0 1 1
0 1 1 0 0 0 1 1
0 1 0 1 0 1 0 1
0 0 1 0 1 0 1 1
0 0 0 1 1 0 1 1

CONTINGENT, SATISFIABLE, NOT A LOGICAL TRUTH

18. [Exercise 18] ¬(p ∨ q) ↔ ¬r ∨ ¬q
p q r ¬r ¬q p ∨ q ¬(p ∨ q) ¬r ∨ ¬q ¬(p ∨ q) ↔ ¬r ∨ ¬q
1 1 1 0 0 1 0 0 1
1 1 0 1 0 1 0 1 0
1 0 1 0 1 1 0 1 0
1 0 0 1 1 1 0 1 0
0 1 1 0 0 1 0 0 1
0 1 0 1 0 1 0 1 0
0 0 1 0 1 0 1 1 1
0 0 0 1 1 0 1 1 1

CONTINGENT, SATISFIABLE, NOT A LOGICAL TRUTH

19. [Exercise 19] ¬(p ∨ q) ↔ ¬p ∨ ¬r
p q r ¬p ¬r p ∨ q ¬(p ∨ q) ¬p ∨ ¬r ¬(p ∨ q) ↔ ¬p ∨ ¬r
1 1 1 0 0 1 0 0 1
1 1 0 0 1 1 0 1 0
1 0 1 0 0 1 0 0 1
1 0 0 0 1 1 0 1 0
0 1 1 1 0 1 0 1 0
0 1 0 1 1 1 0 1 0
0 0 1 1 0 0 1 1 1
0 0 0 1 1 0 1 1 1

CONTINGENT, SATISFIABLE, NOT A LOGICAL TRUTH

20. [Exercise 20] ¬(p → q) ↔ (p ∧ r)
p q r p ∧ r p → q ¬(p → q) ¬(p → q) ↔ p ∧ r
1 1 1 1 1 0 0
1 1 0 0 1 0 1
1 0 1 1 0 1 1
1 0 0 0 0 1 0
0 1 1 0 1 0 1
0 1 0 0 1 0 1
0 0 1 0 1 0 1
0 0 0 0 1 0 1

CONTINGENT, SATISFIABLE, NOT A LOGICAL TRUTH

 

 

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